(4x^3-4x^2+3x+2)-(3x^2+2x-7)=

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Solution for (4x^3-4x^2+3x+2)-(3x^2+2x-7)= equation: 


Simplifying
(4x3 + -4x2 + 3x + 2) + -1(3x2 + 2x + -7) = 0

Reorder the terms:
(2 + 3x + -4x2 + 4x3) + -1(3x2 + 2x + -7) = 0

Remove parenthesis around (2 + 3x + -4x2 + 4x3)
2 + 3x + -4x2 + 4x3 + -1(3x2 + 2x + -7) = 0

Reorder the terms:
2 + 3x + -4x2 + 4x3 + -1(-7 + 2x + 3x2) = 0
2 + 3x + -4x2 + 4x3 + (-7 * -1 + 2x * -1 + 3x2 * -1) = 0
2 + 3x + -4x2 + 4x3 + (7 + -2x + -3x2) = 0

Reorder the terms:
2 + 7 + 3x + -2x + -4x2 + -3x2 + 4x3 = 0

Combine like terms: 2 + 7 = 9
9 + 3x + -2x + -4x2 + -3x2 + 4x3 = 0

Combine like terms: 3x + -2x = 1x
9 + 1x + -4x2 + -3x2 + 4x3 = 0

Combine like terms: -4x2 + -3x2 = -7x2
9 + 1x + -7x2 + 4x3 = 0

Solving
9 + 1x + -7x2 + 4x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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